• No products in the basket.

Percentage Test Question with Solution – TNPSC Aptitude Video Class

[vc_row][vc_column][vc_column_text]

Test Question With Solution – Percentage 

[/vc_column_text][vc_column_text]1.50 kg is what percent of 250 kg?

a) 26%      b) 15%      c)20%      d) 18%[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%23113af4″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491036277627-2f0fc1f4-0e1e” use_custom_heading=”true”]Here Percentage is asked, so, Formula 1

(50/250) x 100

= 20%

Answer ==> C) 20%[/vc_toggle][vc_column_text]2.If 20% of x= 90, find x.

a) 350        b) 450       c) 250       d) 550[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%233804f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491036605984-c85ac97e-0bf6″ use_custom_heading=”true”]Here percentage is given,

20% of x = 90

x X (20/100) = 90

x = (90 x 100)/20

x = 450

Answer ==> b) 450 [/vc_toggle][vc_column_text]3. What is 5% of 50% of 500?

a) 12.5       b) 25      c) 1.25      d)6.25[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230602f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491037121201-6312614a-8a91″ use_custom_heading=”true”]5 % of 50 % of 500

Let us take : 50 % of 500

then [500 x(50/100)]

Now, 5% of [500 x(50/100)]

Therefore, [500 x (50/100)] x (5/100) = 25/2

=12.5

Answer ==> a) 12.5[/vc_toggle][vc_column_text]4. A person’s salary has increased from Rs. 7200 to 8100. what is the percentage increase in salary?

a) 25 %        b)18 %         c)16 2/3 %       d)12  1/2 %[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230d09ef” custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491037517145-7c0b1700-068b” use_custom_heading=”true”]

% change = (change in value / initial value) x 100

change in value = 8100 – 7200

= 900

% change = (900/7200) x 100

=12.5

Answer ==> d) 12 1/2[/vc_toggle][vc_column_text]5. The strength of a college was 3000 last year. If there is an increase of 20 % this year the the present strength is

a) 3200         b) 3400       c) 3600       d) 3800[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230300e8″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491040160481-60d91a4d-de60″ use_custom_heading=”true”]

Strength = 3000

increment = 3000 x (20/100)

= 600

present strength = 3000 + 600

= 3600

Answer ==> c) 3600[/vc_toggle][vc_column_text]6. In a company, there are 724 employees. 25 % employees left the job. Find the number of rest of employees.

a) 543       b) 550       c) 578      d) 565[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%233004f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491040443956-a13fc553-6920″ use_custom_heading=”true”]

Total employees = 724

25 % of 724 = 724 x (25/100)

= 181

181 employees left the company.

therefore, 724 – 181 = 543

Answer ==> a) 543[/vc_toggle][vc_column_text]7. The population of a town is 126800 increases by 15% in the first year and decreases by 20 % in the second year. What is the population of the town at the end of second year?

a) 174984       b) 135996        c) 116656      d) 145820[/vc_column_text][vc_column_text]8) The length of a rectangle is increased by 50%. By what percent would the breadth have to be decreased to maintain the same area?

a) 37.5 %             b) 33.33 %           c) 25 %            d) None of these.[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491284102390-1a138778-b6bf” use_custom_heading=”true”]

 area of rectangle = L x B

let initial L = 100% B = 100%

So, area = 100 x 100 = 10000

length is increased by 50 %, New length = 150

area = 150 x b = 10000 (same area)

b = 10000/150

b = 66.66 %

Question is By what % breadth have to be decreased?

So, % change = (change in value)/(Initial Value x 100)

                         = [(100 – 66.66%)/100] x 100

                         = 33.33 %

Answer = b) 33.33 %[/vc_toggle][vc_column_text]9) Find the percentage increase in the area of a triangle if its each side is doubled.

a) 100 %             b) 200 %           c) 300 %            d) 400 %[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1495121873962-e73a0090-2a24″ use_custom_heading=”true”]

area = 1/2 bh

If sides are doubled, then b = 2b; h = 2h

Then, area = 1/2 (2b x 2h)

= 2bh

% difference = ((Final value – Initial Value)/Initial Value ) X 100

= ((2bh – 0.5 bh) / 0.5 bh) X 100

= 1.5 x 2 x 100

= 300 %

[/vc_toggle][vc_column_text]10) Ramesh spent 20% of his pocket money on buying clothes. After spending 25% of the remainder in buying shoes,  he has Rs.480 left. What was his pocket money?

a) Rs.600             b) Rs.800           c) Rs.900            d) Rs.1000[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1495122153569-59eb8c7f-24b6″ use_custom_heading=”true”]

Let the total pocket money be Y.

Rupees spent on clothes is Y * 20/100

The remaining amount after spending on clothes is,

Y  –  (20Y/100)  ;    [  Y -> Total ;      (20Y/100) -> Clothes ]

=  (100Y – 20Y)/100

= 80Y/100

25 % of the above remainder is spent on shoes, therefore

25 % of (80Y/100)  =   (25/100) * (80Y/100)

= (80Y * 25) / 10000

= 2000 Y / 10000

Therefore, Total Money Y = (20Y/100) + (2000Y/10000) + 480

     (clothes)      +    (shoes)                + (remaining left)

Y = (2000Y  +   2000 Y  +  4800000 ) / 10000

Y = (4000 Y + 4800000 ) / 10000

10000 Y = 4000 Y + 4800000

10000 Y – 4000 Y = 4800000

6000 Y = 4800000

Y = 4800000 / 6000

Y = 800 rupees

[/vc_toggle][vc_column_text]

Watch TNPSC Aptitude video class in Tamil & English – Percentage

[/vc_column_text][/vc_column][/vc_row]

18 responses on "Percentage Test Question with Solution - TNPSC Aptitude Video Class"

  1. I am not able to derive the answer for 7th question( Population related). Also it looks like solution steps are not provided. Please check and upload the solution steps for that question which will be very useful. Thanks in Advance.

  2. Please update solution for 7th question. I guess answer is c)116656

  3. Where is the answers

  4. 1 2

Leave a Message

Your email address will not be published. Required fields are marked *

© TNPSC.Academy | All Rights Reserved.